If a load exceeds the ultimate yield for metals, what happens?

If a load exceeds the ultimate yield for metals, what happens?

• A. Metal will bend and recover
• B. Metal will crack and break
• C. Metal will fuse
• D. Metal will corrode

Answer: (B)

When a metal is loaded beyond its yield strength, it stops behaving elastically and begins to deform plastically, meaning the deformation is permanent. If you continue to increase the load after yielding, the material accumulates further plastic deformation and can develop cracks that propagate until the structure can no longer carry the load, resulting in fracture. So the description of cracking and breaking captures the sequence from yielding to ultimate failure under continued overloading. The other scenarios don’t fit this mechanical overloading context: bending and recovering would require purely elastic behavior with no permanent deformation, fusing is a thermal/wusing outcome not caused by ordinary mechanical overloading, and corrosion is chemical degradation rather than a mechanical failure mode.

When a metal is loaded beyond its yield strength, it stops behaving elastically and begins to deform plastically, meaning the deformation is permanent. If you continue to increase the load after yielding, the material accumulates further plastic deformation and can develop cracks that propagate until the structure can no longer carry the load, resulting in fracture. So the description of cracking and breaking captures the sequence from yielding to ultimate failure under continued overloading.

The other scenarios don’t fit this mechanical overloading context: bending and recovering would require purely elastic behavior with no permanent deformation, fusing is a thermal/wusing outcome not caused by ordinary mechanical overloading, and corrosion is chemical degradation rather than a mechanical failure mode.